Draw The Graph Of The Function Y X2 4x 6 Mathematics Topperlearning Com Knyzd6o11
X^ {2}4x=y3 Subtract 3 from both sides x^ {2}4x\left (2\right)^ {2}=y3\left (2\right)^ {2} Divide 4, the coefficient of the x term, by 2 to get 2 Then add the square of 2 to both sides of the equation This step makes the left hand side of the equation a Then you need to determine 3 sets of coordinates that characterize your parabola 1) The Vertex this is the lowest point of your parabola (the bottom of your U) to find its coordinates (x_v and y_v) you use the fact that x_v=b/(2a) and y=Delta/(4a) Where Delta=b^24ac 2) Crossing point with the y axis This point has coordinates (0, c) 3) Crossing point(s) with the x