Click here 👆 to get an answer to your question ️ 2√3x^2 5x √3 = 0 using quadratic formula loveableoneloveableo loveableoneloveableo Best answer 2√3x2 ˗ 5x √3 ⇒ 2√3x2 ˗ 2x ˗ 3x √3 ⇒ 2x (√3x ˗ 1) ˗ √3 (√3x ˗ 1) = 0 ⇒ (√3x ˗ 1) or (2x − √3) = 0 ⇒ (√3x ˗ 1) = 0 or (2x − √3) = 0 ⇒ x = 1 3 or x = 3 2 ⇒ x = 1 3 x 3 3 = 3 3 or x = 3 24√3 x^25x2√3=0 Find the Zeros of the following quadratic polynomials and verify the relationship between the zeros and their coefficients4 Root 3 x^25x
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3/5x^2-2/3x+1=0
3/5x^2-2/3x+1=0- Solve the quadratic equation 4√3x^25x2√3=0 Get the answers you need, now! Find the zeros of the quadratic polynomials 2√3 x2 – 5x √3 and verify the relationship between the zeros and the coefficients
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0 votes 1 answer Find the roots of the following equations, if they exist, by applying the quadratic formula 2√3x^2 5x √3 = 0 asked Jul 13 in Quadratic EquationsDiscriminant of the quadratic equation √5x^2 3 √3x 2 √5 = 0 is Find the zeroes of the polynomial f(x) = 2√3x^2 ˗ 5x √3 and verify the relation between its zeroes and coefficients asked Jun 17 in Polynomials by Hailley (
Factorise 4√3 x^2 5x 2√3=0Factorise 4 Root 3x2 5x 2 Root 3=0Find the solution of the quadratic equation 3√3x^2 10x √3 = 0 asked 4 days ago in Quadratic Equations by Devakumari (102k points) quadratic equations;Subscribe https//youtubecom/c/GRAVITYcoachingInstituteCBSE Previous Years Questions Class(X) Qu(2) Solve the equation for x 4√3x^2 5x – 2√3 = 0
21 Factoring 5x25x3 The first term is, 5x2 its coefficient is 5 The middle term is, 5x its coefficient is 5 The last term, "the constant", is 3 Step1 Multiply the coefficient of the first term by the constant 5 • 3 = 15 Step2 Find two factors of 15 whose sum equals the coefficient of the middle term, which is 5 4√3x^25x2√3=0 Solve the quadratic equation Asked by vijayalakshmiputravu 4th Mar, 19, 0746 PM Expert Answer 4√3 x 2 5x 2√3 = 0Ayushigupta563 ayushigupta563 Math Secondary School answered Solve the quadratic equation 4√3x^25x2√3=0 2 See answers
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Find the roots of the equation 4√3x^2 5x – 2√3 = 0 if they exist, by applying the quadratic formula asked in Quadratic Equations by Vevek01 ( 472k points) quadratic equationsClick here 👆 to get an answer to your question ️ 2√3x^25x√3 factories it hiteshkr4 hiteshkr4 Math Secondary School 2√3x^25x√3 factories it 1 See answer hiteshkr4 is waiting for your help Add your answer and earn pointsThe given equations is 2√3x 2 5x √3 = 0 Comparing it with ax 2 bx c = 0we get a = 2√3, b = 5 and c = √3 ∴ Discriminant, D = b 2 4ac = (5) 2 4 x 2√3 x √3 = 25 25 = 1 > 0 So, the given equation has real roots Now, √D = √1 = 1 Hence, √3/2 and
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